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maxonik [38]
3 years ago
11

Please help me with this question

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0

Answer:

35

Step-by-step explanation:

3 + 8 x 4 =

3 + 32     =

35

Hope this helps! Please mark as brainliest.

Evgen [1.6K]3 years ago
7 0

Answer:

35

but why do you need help you already chose the answer

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HELP PLEASEEEE!!!!!!!!
nikdorinn [45]
Chin is correct because 5 x $.65 is $3.25., and he multiplied by US/GB

Nadene is incorrect because she took GB/US x 5
3 0
3 years ago
Which of the following is a radical equation?<br> Ox√3=13<br> O x+√3=13<br> O√x+3=13<br> O x+3=√13
sashaice [31]

Answer:

The answer would be: √x+3=13

Step-by-step explanation:

A radical equation is an equation with at least one variable put on a radical form. In this question, there is only one kind of variable which is x. Then, you need to find the equation where x is in the radical form. The radical form can be expressed with square root symbol.

The option with √x would be only √x+3=13

8 0
2 years ago
​PLEASE HELP! I will give you the brainiest and A LOT of points!
Alja [10]

Answer:The solution is in the attached file

Step-by-step explanation:

7 0
3 years ago
If the mean if these numbers is 9 what is x ? <br><br> 16,3,x,5
siniylev [52]
The mean is the average number meaning that it is all the numbers in a set added together and divided by how many number are in the set. In this case there are 4 numbers (16, 3, whatever number x is, and 5). So, to find out what x is, first you multiple 4 by the known mean which is 9.
4 x 9 = 36
Then you simply subtract 36 from all the known numbers to find x.
36 - 16 - 5 - 3 = 12
So x = 12
5 0
3 years ago
Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


5 0
3 years ago
Read 2 more answers
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