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3 years ago

Solve:

" alt="3x {}^{2} - 10x - 8" align="absmiddle" class="latex-formula">
please someone help me

Mathematics

1 answer:

Marizza181 [45]3 years ago

5 0

(x-4)(3x+2) is your answer

3x²-10x-8

3x²-(12-2)x-8

3x²-12x+2x-8

3x(x-4)+2(x-4)

(x-4)(3x+2)

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The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct

Zarrin [17]

The functions would be:

D. y=x³

We can check it out.

(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125

8 0

3 years ago

When you solve an equation, you must

MAXImum [283]

Answer:

x is equal to 6

Step-by-step explanation:

4x=24

divide both sides by 4

4 eliminates 4 leaving x behind

4 divides 24 making x =6

3 0

4 years ago

Please help me find total surface area

vredina [299]

Answer:

2(lw + wh + hl)

2×71

142

this is the answer

5 0

2 years ago

Read 2 more answers

What number would you add to both sides of x2 + 7x = 4 to complete the square? A.2^2 B.7^2 C, 7^2/2 D.(7/2)^2

Lostsunrise [7]

The answer is d. (7/2)^2

7 0

3 years ago

Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)

andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

QR= $\sqrt{100+100}$

QR= $\sqrt{200}$ --------------------------(1)

QR=14.142136

RS= $\sqrt{(9-(-3))^2+(-8-0)^2}$

RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

RS= $\sqrt{208}$ ---------------------------(2)

RS=14.422205

QS= $\sqrt{(7-9)^2+(-10-(-8))^2}$

QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

$(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2$

$208 = 200 +8$

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0

3 years ago