3 years ago

Select the correct answer.

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

AlekseyPX3 years ago

4 0

Answer:

Option c is the correct answer if the answer is correct plz mark me as brainliest.

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forsale [732]

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Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

$\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|$

(a)Mean

Expected Value, $\mu =\sum x_iP(x_i)$

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

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(b)Standard Deviation

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Standard Deviation $=\sqrt{\sum (x-\mu)^2P(x)}$

$=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765$

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

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