Transform the following formulas as indicated.

A bicycle tire has a radius of 11 inches. To the nearest inch, how far does the tire travel when it makes 7 revolutions?

jok3333 [9.3K]

Answer:

d = 483.56 inches

Step-by-step explanation:

We have,

Radius of a bicycle tire is 11 inches. It is required to find the distance traveled by the distance covered by the tire when it makes 7 revolutions. One revolution means the circumference of circle. So,

$C=2\pi r\\\\C=2\times 3.14\times 11\\\\C=69.08\ \text{inches}$

In 7 revolution, it will cover a distance of 7C i.e.

$C=69.08\times 7\\\\C=483.56\ \text{inches}$

So, the tire will cover a distance of 483.56 inches in 7 revolutions

8 0

3 years ago

Find the value of y. (6x - 13) (3y + 1) (8x - 61)

Korolek [52]

Answer:

y=1/3

Step-by-step explanation:

3y+1=0

3y=-1

3y/3=-1/3

y=-1/3

6 0

3 years ago

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse B A is 9.8 inches, the length of C B is 6.3 inch

german

Answer:

$\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)$

Step-by-step explanation:

Consider right triangle ABC with right angle C.

In this triangle,

BA = 9.8 in
CB = 6.3 in
CA = 7.5 in

Write trigonometric functions:

$\cos \angle B=\dfrac{BC}{AB}=\dfrac{6.3}{9.8}\\ \\\sin \angle B=\dfrac{AC}{AB}=\dfrac{7.5}{9.8}$

Hence,

$\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)$

7 0

3 years ago

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Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

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3 0

3 years ago

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What is bigger 3/4 or 3/8

Naya [18.7K]

3/4 is bigger. 3 divided by 4 is 0.75. 3 divided by 8 is 0.375

5 0

3 years ago

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