Not sure if you’re speaking Spanish or not but yes
The standard form is y=4/3+4.
Using the z-distribution, it is found that:
- The 95% confidence interval is of -1.38 to 1.38.
- The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.
<h3>What is the z-distribution confidence interval?</h3>
The confidence interval is:

In which:
is the difference between the population means.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The estimate and the standard error are given by:

Hence the bounds of the interval are given by:


1.74 is outside the interval, hence:
- The 95% confidence interval is of -1.38 to 1.38.
- The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer: (32/2)*3=48
Step-by-step explanation:
In order to find the answer, we must find one third of last year's trip. To do this, we can simply divide the cost of this years trip by two, 32/2=16.
Now if we multiply this this number by 3, 16*3=48, we can see that the total cost of last year's trip was $48.
If we'd like to turn this into one equation, it looks like this: (32/2)*3=48