Hello,
P=0.72^(3/2)=0.610940...years=223.1398...days
Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

Now all we have to do is solve the equation for v:







As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
Chocolate thickshakes will cost $5 and fruit smoothies will cost $3. Let's say the cost of chocolate thickshakes are x and the cost of fruit smoothies are y.
3x + 4y = 27
3x + 3y = 24
Answer:
Average rate of chage = [change of y] / [change of x] = [- 10.125 - (-.35)] /[4 - 2] =
= -3.3125
Answer: option B.
Step-by-step explanation:
please mark as brillant