The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
^n=1/square root of 59 (535) ,if that makes sense its hard to type it
Yes, you must first link the problem with your question
Δ=88
1) Using the Quadratic Equation to Solve
3x²-8x+1=3
3x²-8x+1-3=3-3
3x² -8x -2=0
2)Let's find the discriminant
Δ= (-8)²-4(3)(-2)
Δ=64 -4(3)(-2)
Δ=88