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Natasha_Volkova [10]
3 years ago
11

Simplify. 9/3x + 4+ 2x

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

5x+4

Step-by-step explanation:

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PLEASE HELP ASAP WILL MARK BRANLIEST<br><br> did i get the right answer or is it wrong?
Nesterboy [21]

Answer:

<h2><em><u>62</u></em><em><u>.</u></em><em><u>2</u></em></h2>

Step-by-step explanation:

4n × 2 + 43

<em>[</em><em>By</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em>]</em>

= (4 ×2.4) × 2 + 43

= 9.6 × 2 + 43

= 19.2 + 43

= <em><u>62.2 (Ans)</u></em>

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Factorize 10x3y2+5x3y3-15x4y5
d1i1m1o1n [39]

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−5x^3y^2(3xy^3−y−2)

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Equivalent fractions using the LCD 7/10 and 2/5
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How to change the expression to a single logarithm
IrinaK [193]
First, you'll use the "Log power rule," which says that \log_ax^p=p\log_ax. In this case, you're going from the form on the right (with p in front of the log) to the form on the left (with p in the exponent position). So, the expression becomes:

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Then, you'll use the "Log product rule," which says that \log_a(xy)=\log_ax+\log_ay. Again, you're going from the form on the right to the form on the left (basically, from the sum of the logs, to a log of the products). So you get:

\log_7(x^4y^8z^4)

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