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AlekseyPX
3 years ago
5

Find three consecutive odd integers so that the sum of twice the first, the second

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

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I think that the answer isssss B

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3 years ago
Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
jeyben [28]

f(0) = 2(3)(0) = 0  ⇒  (0, 0)

f(1) = 2(3)(1) = 6  ⇒  (1, 6)

<u>rate of change from x = 0 to x = 1</u>

\frac{y2 - y1}{x2 - x1} = \frac{6 - 0}{1 - 0} = \frac{6}{1} = 6

******************************************

f(2) = 2(3)(2) = 12  ⇒  (2, 12)

f(3) = 2(3)(3) = 18  ⇒  (3, 18)

<u>rate of change from x = 2 to x = 3</u>

\frac{y2 - y1}{x2 - x1} = \frac{18 - 12}{3 - 2} = \frac{6}{1} = 6

*****************************************

Since it is the same line, they will have the same slope (aka rate of change).

5 0
3 years ago
Ruth has 6 chores to do. If each chore does not depend on the others, in how many different orders could she do the chores?
Mice21 [21]
First chore, 6 to choose from.
Second chore, 5 to choose from.
Third chore, 4 to choose from.
Fourth chore, 3 to choose from.
Fifth chore, 2 to choose from.
Sixth chore, 1 to "choose" from.
The total number of orders possible is the product
6*5*4*3*2*1=6!=720
3 0
3 years ago
Read 2 more answers
Chicken Delight claims that 87% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 80 or
jeka57 [31]

Answer:

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

Step-by-step explanation:

In this question we have to test an hypothesis.

The null and alternative hypothesis are:

H_0: \pi\geq0.87\\\\H_a:\pi

The significance level is assumed to be 0.01.

The sample of size n=80 gives a proportion of p=61/80=0.7625.

The standard deviation is:

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }=\sqrt{\frac{0.87*0.13}{80} }=0.0376

The statistic z is then

z=\frac{p-\pi+0.5/N}{\sigma}=\frac{0.7625-0.87+0.5/80}{0.0376} } =\frac{-10125}{0.0376} =-2.70

The P-value is

P(z

The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

6 0
3 years ago
Simplify the product using FOIL (3x+4) (2x-6)
____ [38]
(3x+4) (2x-6)
6x-18x+4x-24
6x^{2} -14-24
5 0
3 years ago
Read 2 more answers
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