Answer:
8 units
Step-by-step explanation:
Since both are on the same place in terms of the x-axis, this makes it much easier. Just go from (-1,4) and move upwards upon the graph until your at (-1,12). You counted 8 units. *mic drop*
In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
For this case we observe that the three angles of the triangle are equal. Also, we have by definition:
A triangle is equilateral, when the three sides have the same length (in addition, the three internal angles measure 60 degrees or
.
Answer:
The three sides have the same length
Answer:
So angle 3 is congruent to angle 4 because they are both complimentary to 1 and 2.
By SAS, triangle SNM is congruent to triangle SNF.
By CPCTC, angle QMN is congruent to angle RFN.
By AAS, triangle QMN is congruent to RNF.
So by CPCTC, QM=RP