Since drapes have to be covered all over the window and the beneath of the window, both lengths have to be added.
(2 2/3) + ( 2 3/4)
(8/3) + (11/4)
(32+33)/12
65/12
5 5/12
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
{3x+2y=4 /*5
{4x+5y=17 /*(-2)
{15x+10y=20
<u>{-8x-10y=-34 </u>(+)
<em>7x=-14</em><em />
<em>x=-2</em>
15x+10y=20
15*(-2)+10y=20
-30+10y=20
10y=50
<em>y=5</em>
