All categories

1 year ago

MATH

Mathematics

2 answers:

Kryger [21]1 year ago

8 0

Answer:

f(-4)=-2, f(4)=-4, f(0)=-4

Step-by-step explanation:

-4 is less than -3, so you would input it for that equation, your answer would be -2.

4 is greater than 1, so you would input it for that equation, your answer would be -4

0 is between -3 and 1, so you would input it for that equation, your answer would be -4

olchik [2.2K]1 year ago

5 0

Answer:

f(-4) = -2

Step-by-step explanation:

To find f(-4) use the "piece" of the function rule defined for x < -3 (because -4 is less than -3). That part of the rule says the output (range) value is x + 2, so f(-4) = -4 + 2 = -2.

You might be interested in

Six times the sum of a number and 8 is 2

ehidna [41]

6(n+8)=2
6n + 48 = 2
6n + 48 - 48 = 2 - 48
6n = -46
N = -46/6
N = -7 2/3

4 0

3 years ago

Select steps that could be used to solve the equation 1 + 3x = -x + 4.

Tema [17]

For this case we have the following equation:

$1 + 3x = -x + 4$

We must solve the equation by following the steps below:

We subtract 1 from both sides of the equation:

$3x = -x + 4-1$

On the right side of the equation we have that different signs are subtracted and the sign of the major is placed:

$3x = -x + 3$

We add x to both sides of the equation:

$3x + x = 3\\4x = 3$

We divide between 4 on both sides of the equation:

$x = \frac {3} {4}$

Thus, the correct option is option B

Answer:

$x = \frac {3} {4}$

Option B

6 0

3 years ago

Read 2 more answers

Alina has just received 333 video games for her birthday to add to her existing 121212 video games. A week later she went to the

Katarina [22]

[(121212+333)(2)]+555

7 0

2 years ago

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

$\dfrac{A}{A'}=\dfrac{P^2}{P'^2}$

We are given:

A=72 dm^2 , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. $\dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}$

on taking square root on both the side we get:

$\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'$

Now putting the value of P in equation (1) we obtain:

$\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272$

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0

3 years ago

Am trying to find the value of r<br> 1/r + 2/1-r = 4/r^2

Mashcka [7]

<span>1/r + 2/1-r = 4/r^2

1-r+2r/r(1-r)=4/r^2
(1+r)/r(1-r)=4/r^2 cancle r both side

1+r/1-r=4/r

cross multiply
r+r^2=4-4r
r^2+4r+r-4=0
r^2+5r-4=0
r^2+4r+r-4=0
solve it for r factor it...

</span>

6 0

2 years ago