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Naddika [18.5K]
3 years ago
7

Estimate than find the product 503x7

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0
Estimation: 500×7=3,500
Product: 503×7=3,521
aleksklad [387]3 years ago
4 0
Answer 3524 because I times it
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helpppppppppppppppp need now--------------------------------------------------Manuel borrowed $1,500 from his bank and signed a
Sedaia [141]
Answer: I think it’s 225
Explanation: 1,500 • .15= 225
3 0
3 years ago
Milan drove 715 miles in 11 hours. At the same rate, how many miles would he drive in 9 hours?
Gwar [14]

Answer:

585 miles

Step-by-step explanation:

Basically since he drove 715 miles in 11 hours you would have to divide the 2 numbers then you get 63.

63 is the rate so then you multiply by 9 hours then that's your miles.

585 miles

7 0
3 years ago
A red light flashes every 14 minutes. A blue light flashes every 24 minutes. when will the two lights flash together again if th
natta225 [31]
14×12=168

24×7=168

168÷60=2 hours and 48 minutes

2 hours and 48 minutes+ 8:00AM=10:48AM

Answer: 10:48AM 

4 0
3 years ago
Please help me.................​
schepotkina [342]

Answer:

A

Step-by-step explanation:

because if 8 is g that makes the top 8 and 2+3 eaquls five. this is simple

3 0
3 years ago
The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the
jolli1 [7]
If you've started pre-calculus, then you know that the derivative of  h(t)
is zero where h(t)  is maximum.

The derivative is            h'(t) = -32 t  +  96 .

At the maximum ...        h'(t) = 0

                                       32 t = 96 sec

                                           t  =  3 sec . 
___________________________________________

If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.

In that case, the question GIVES you the maximum height.
Just write it in place of  h(t), then solve the quadratic equation
and find out what  't'  must be at that height.

                                       150 ft = -16 t²  +  96  t  +  6 

Subtract 150ft from each side:    -16t²  +  96t  -  144  =  0 .

Before you attack that, you can divide each side by  -16,
making it a lot easier to handle:

                                                         t²  -  6t  +  9  =  0

I'm sure you can run with that equation now and solve it.    
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.  
(Funny how the two widely different methods lead to the same answer.)

The answer is from AL2006

6 0
4 years ago
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