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k0ka [10]
2 years ago
8

What is the product?

Mathematics
1 answer:
KATRIN_1 [288]2 years ago
4 0

Answer: 4y/(y+3)

Explanation:

{(2y)(4y-12)}/{(y-3)(2y+6)}

= (8y^2 - 24y)/(2y^2 + 6y - 6y - 18)

= (8y^2 - 24y)/(2y^2 - 18)

= {8y(y-3)}/{2(y+3)(y-3)}

= 2 * 4y/{2(y+3)}

= 4y/(y+3)

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A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig
Anika [276]

Answer:  (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Sample size = 463

\mu=118\text{ minutes}

\sigma=65\text{ minutes}

Significance level : \alpha=1-0.99=0.01

Critical value : z_{\alpha/2}=z_{0.005}=\pm2.576

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0
3 years ago
Can sum1 explain on how to do 1 &&' 2
HACTEHA [7]

what times it self is 36 answer the square root of 86

the same for the second 1

6 0
2 years ago
X Y
aliina [53]
The answer is B. I hope it help :)
4 0
2 years ago
There is 4/6 of a pizza left from dinner . Each person gets 1/6 of a pizza for lunch the next day . How many people eat the pizz
Goryan [66]

The number of people which gets 1/6 of the pizza as required for lunch the next day is; 4 persons.

<h3>What is the number of people who get 1/6 of the pizza for lunch?</h3>

It follows from the task content that only 4/6 of the pizza is left and each individual needs 1/6 of the pizza for lunch.

On this note, the 4/6 fraction of pizza left mean: 4 × 1/6.

Therefore, only four persons get lunch.

Read more on fractions;

brainly.com/question/17220365

#SPJ1

8 0
2 years ago
PLEASEEE HELLPPP!!!!!!!!
belka [17]

Answer:

4.25 i think

Step-by-step explanation:

sorry i    have not done these in a while it might be wrong

5 0
3 years ago
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