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Verizon [17]
3 years ago
10

5x + 1 = 56 Solving 2 step equations?

Mathematics
1 answer:
frutty [35]3 years ago
4 0

Answer:

the x would equal to 11 ,so x=11

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Please I need help I’m giving 20 points for the answer please
strojnjashka [21]

Answer:

I would answer but in your question you said you are giving away 20 points when you are only giving away 15.... Make sure to state facts only.


Step-by-step explanation:

I'll answer anyways.....

You can make 0 different triangles. The angles/points would never line up right to make a triangle. Sorry if I'm wrong but I'm pretty sure this is right.

*If this helped Plz mark Brainliest*


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Read 2 more answers
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
Please help I don't understand!
coldgirl [10]

Answer:

AB

Step-by-step explanation:

I believe because on the other side it is AE over ED so I just repeated the pattern.

6 0
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Evaluate f(x) = -x to the second power + 1 for x = -3
professor190 [17]
I think it's 4 Yeah 4 something like that
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