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MA_775_DIABLO [31]
3 years ago
14

A bag has 5 blue marbles, 3 red marbles, and 2 green marbles. We draw two marbles, one at a time, with replacement. What is the

probability that the first draw will be blue and the second draw will be green?
Mathematics
1 answer:
VMariaS [17]3 years ago
6 0

Answer: \frac{1}{10}

<u>Step-by-step explanation:</u>

Blue = 5, Red = 3, Green = 2, Total = 10

Probability   =  First draw    and      Second draw

                    =        \frac{5}{10}             x                 \frac{2}{10}      

                    =                      \frac{10}{100}

                    =                       \frac{1}{10}        

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On any given day, the number of users, u, that access a certain website can be represented by the inequality 125-4530
Masteriza [31]

Answer:

Step-by-step explanation:

Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.

Therefore, we now have two inequalities to solve for:

125-u ≤ 30

u-125≤30

For the first one, we can subtract 125 and add u to both sides, resulting in

0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.

The second one can be figured out by adding 125 to both sides, so u ≤ 155.

Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,

u ≥ 95

and

u ≤ 155

combine to be

95 ≤ u ≤ 155, or the 4th option

4 0
3 years ago
Heyo, please don't ignore! i really need help on these questions
Sauron [17]

Answer:

times

21.12

28

I will pay 11.20 and get back .20 for the half(.5) of a drink box I can't buy

Step-by-step explanation:

7 0
3 years ago
Find the equation of the graphed line.
GrogVix [38]

Answer:

  a.  y = -1/2x - 2

Step-by-step explanation:

The correct answer choice can be determined by finding the slope of the line. The slope is the ratio of rise to run.

__

<h3>slope</h3>

The x-intercept is 4 units left of the y-axis. As the line "runs" those 4 units, it "rises" -2 units to intercept the y-axis at -2. The slope of the line is ...

  m = rise/run = -2/4 = -1/2

In the slope-intercept form of the equation of a line, the slope is the coefficient of x. This information is sufficient to let us choose the first answer choice.

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<h3>equation</h3>

The slope-intercept equation is ...

  y = mx +b . . . . . . . slope m, y-intercept b

We know the slope is -1/2, and the y-intercept is where x=0, at y=-2. Then the equation is ...

  y = -1/2x -2 . . . . . matches choice A

_____

<em>Additional comment</em>

When answering multiple-choice questions, you only need to do enough work to tell which answers are <em>not</em> viable.

When we plot the points, we see that the line has negative slope. (eliminates choice C). The slope is shallow, rather than steep (the x-intercept is farther from the origin than the y-intercept), so the magnitude of the slope is less than 1 and choices B and D are eliminated.

8 0
2 years ago
I need help, I dont know how to convert ratios into decimals and percentages [EX: write the ratio 5 to 8 in a decimal/percent]​
Anon25 [30]
Fractions are just unsimplified numbers. For example 5/8 is just 5 divided by 8 so 0.625. To find the percent from that you move the decimal two places to the right making it 62.5%. Hope this helps!
5 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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