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vova2212 [387]
3 years ago
10

Find the measure of angle 2 and 3​

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer: angle 2 is 38

Angle 3 is 79

Step-by-step explanation:

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Vector Vector P Q has an initial point at (3, 3) and its terminal point is at (5, 7). Vector Vector R S has an initial point at
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5,3

Step-by-step explanation:

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Find the antiderivative for each function when C = 0. Check your answers by differentiation. ​
leonid [27]

Answer with Step-by-step explanation:

We are given that C=0

We have to find the anti-derivative of each function

a.h(x)=sec^2 x

We know that \int sec^2 xdx=tanx+C

Apply this formula then, we get

\int sec^2x dx=tanx +C

Substitute C=0

Then, we get \int h(x) dx=tan x

Verification :

Differentiate w.r.t x

Then, we get

h(x)=sec^2 x

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b.g(x)=\frac{8}{9} sec^2 \frac{x}{9}

\int g(x) dx=\frac{8}{9}\int sec^2\frac{x}{9} dx=\frac{8}{9}\times 9tan\frac{x}{9}+C

Substitute C=0

\int g(x) dx=8 tan\frac{x}{9}

Verification:

Differentiate w.r.t x

g(x)=8\times \frac{1}{9} sec^2\frac{x}{9}=\frac{8}{9} sec^2\frac{x}{9}

c.k(x)=sec^2\frac{9x}{8}

\int k(x) dx=\int \sec^28}{9}tan\frac{9x}{8}+C

Substitute C=0

\int k(x) dx=\frac{8}{9} tan\frac{9x}{8}

Verification: Differentiate w.r.t x

k(x)=\frac{8}{9}\times \frac{9}{8} sec^2\frac{9x}{8}=sec^2\frac{9x}{8}

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3 years ago
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What are three ways to get 256 using exponents
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recall from the previous posting, 2⁸ = 256, so that's one way to represent it.

now, another way hmmm


\bf 2^8\implies 2^{2\cdot 4}\implies (2^2)^4\implies (4)^4\implies 4^4
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\stackrel{\textit{yet another way}}{2^8\implies 2^{4\cdot 2}}\implies (2^4)^2\implies (16)^2\implies 16^2

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