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3 years ago

PLEASE HELP DUE IN 30 MINS WILL MARK BRAINLIEST

Mathematics

1 answer:

icang [17]3 years ago

6 0

Answer:

48.55

Step-by-step explanation:

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A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?

avanturin [10]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a cone with base radius 9mm and height 13 mm

To calculate - volume of the cone

We know that ,

$Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h \\$

substituting the values in the formula ,

$Volume = \frac{1}{3} \times 3.14 \times 9 \times 9 \times 13 \\ \\ \implies \: 1.05 \times 81 \times 13 \\ \\ \implies \: 1105.65 \: mm {}^{3}$

hope helpful ~

7 0

2 years ago

Maggie says that if the expression was 12÷3to the second power, you would divide before simplifying 3 to the second power. Is sh

mezya [45]

Answer:

Maggie is incorrect.

Step-by-step explanation:

PEMDAS tells us the order of operations and the steps of solving a mathematical statement. It states that exponents must be performed before multiplication or division.

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Therefore, to solve 12÷3² correctly, 3² needs to be simplified to 9 before dividing.

I hope this helps!

4 0

3 years ago

0.000309 in scientific notation

trasher [3.6K]

Hey there :)

Writing in scientific notation means a should be
0 ≤ a < 10

Therefore, 0.000309 will be written as
3.09 x 10ⁿ

3 is the 4th decimal place value

so n = - 4

3.04 x 10⁻⁴

3 0

3 years ago

Jake has a total of 60 chocolates and sweets for sale.After selling 1/3 of the chocolates and 2/3 of the sweets,he had twice as

sergeinik [125]

Drawing models makes it clearer to compare.

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3 years ago

A bag contains marbles: 5 red, 2 blue, and 1 green. You pick a marble and then another one without replacement. What is the prob

max2010maxim [7]

1st draw: green

2/12. (2 green out of 12 marbles), reduces to 1/6

2nd draw: blue

4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)

Probability of theses BOTH happening: multiply these individual probabilities.

Conditional probability:

P(a and b) = P(a)P(b|a)

Prob(event 1) × Prob(event 2 given event 1).

1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.

5 0

2 years ago