Answer:
= −11.2
Step-by-step explanation:
64.8=6(m+22)
We move all terms to the left:
64.8-(6(m+22))=0
We calculate terms in parentheses: -(6(m+22)), so:
6(m+22)
We multiply parentheses
6m+132
Back to the equation:
-(6m+132)
We get rid of parentheses
-6m-132+64.8=0
We add all the numbers together, and all the variables
-6m-67.2=0
We move all terms containing m to the left, all other terms to the right
-6m=67.2
Answer:
Yes, F is a continuous function of r
Step-by-step explanation:
We are given that
When r<R



Where M=Mass of the earth
R=Radius of earth
G=Gravitational constant
We have to find the function is continuous of r or not.
LHL

RHL


When a function is continuous at x=a
Then, LHL=RHL=f(a)
RHL==LHL=F(R)
Hence, the function is continuous of r.
The right answer for the question that is being asked and shown above is that:
Two numbers have a sum of 71 and a difference of 37
x + y = 71
x - y = 37
So in order to get the two numbers, here it is:
x + y = 71
x - y = 37
------------
2x = 108
x = 54
y = 71 - 54
y = 17
<span>So the two numbers are 54 and 17</span>