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pishuonlain [190]
3 years ago
7

The population of fish in a pond in relation to the number of years since stocking is depicted on a graph. For the first few yea

rs after the pond is stocked, the population grows slowly. It increases more quickly as the fish reproduce, then it levels off. A pollutant kills off almost all of the fish 20 years after stocking. The population begins to grow again when the remaining fish reproduce. Which graph depicts the situation described above? ​

Mathematics
2 answers:
Viktor [21]3 years ago
7 0

Answer:

graph c is the correct answer

luda_lava [24]3 years ago
5 0

Answer:

Graph a

Step-by-step explanation:

the slope is proportional to the data

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Trig please help.
iris [78.8K]

Answer:

24, 40

Step-by-step explanation:

The area of a triangle is given by the formula

A=\frac{1}{2}bh

where

b is the length of the base

h is the length of the height

For the 1st triangle here, we have:

b = 6 is the base

h = 8 is the height

So, the area of the triangle is

A_1=\frac{1}{2}(6)(8)=24

For the 2nd triangle here, we have:

b = 8 is the base

h = 10 is the height

So, the area of the triangle is

A_2=\frac{1}{2}(8)(10)=40

4 0
3 years ago
write the slope intercept equation. the graph of f passes through (-6,4) and is perpendicular to the line that has an x-intercep
Nimfa-mama [501]

Answer:

y = -\frac{1}{3} x + 2

Step-by-step explanation:

The slope of the line that has an x intercept of (2,0) and y-intercept of (0,-6) is:

Slope(s) = Change in y ÷ change in x

s = \frac{0 - -6}{2 - 0} = 3

The slope of the perpendicular line to this line with slope of 3 has to have a slope of -1 ÷ 3 = -\frac{1}{3}

Reason: The product of slopes of lines perpendicular to each other have to be -1

So the slope of the perpendicular line that passes through (-6,4) is -\frac{1}{3}

As mentioned earlier, we derive a slope of a line by dividing the change in y by the change in x

Taking another point (x,y) on the line,

-\frac{1}{3} = \frac{y - 4}{x - -6}

-\frac{1}{3} = \frac{y - 4}{x + 6}

y - 4 = -\frac{1}{3}x - 2

y = -\frac{1}{3}x + 2

5 0
3 years ago
Five and fifty-six<br> thousandths in decimal form
Lerok [7]

Answer:

0.056

Step-by-step explanation:

:) hope this helps

3 0
2 years ago
Read 2 more answers
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
HELP QUICK PLS WILL GIVE BRAINLIEST
alexandr1967 [171]

Answer:

0.08(50h)

Step-by-step explanation:

0.08(50h)+50h=

8/100(50h)+50h=

0.08(50h)+50h

It's 0.08 of 50h, so

0.08(50h)

4 0
3 years ago
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