Answer:
24, 40
Step-by-step explanation:
The area of a triangle is given by the formula
where
b is the length of the base
h is the length of the height
For the 1st triangle here, we have:
b = 6 is the base
h = 8 is the height
So, the area of the triangle is
For the 2nd triangle here, we have:
b = 8 is the base
h = 10 is the height
So, the area of the triangle is
Answer:
y = + 2
Step-by-step explanation:
The slope of the line that has an x intercept of (2,0) and y-intercept of (0,-6) is:
Slope(s) = Change in y ÷ change in x
s = = 3
The slope of the perpendicular line to this line with slope of 3 has to have a slope of -1 ÷ 3 =
Reason: The product of slopes of lines perpendicular to each other have to be -1
So the slope of the perpendicular line that passes through (-6,4) is
As mentioned earlier, we derive a slope of a line by dividing the change in y by the change in x
Taking another point (x,y) on the line,
=
=
y - 4 = x - 2
y = x + 2
Answer:
If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.
Step-by-step explanation:
Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:
the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.
Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:
When we use this to replace the 't" in the displacement formula, we et:
This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)
And we can also answer the question about time, since given the same initial velocity , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)