All categories

3 years ago

(30 points for answering! If you show steps I will give brainliest!)

Mathematics

1 answer:

Serjik [45]3 years ago

3 0

The width of park is $\frac{7}{4}$ miles.

Step-by-step explanation:

Given,

Area of park = $\frac{7}{8}\ square\ miles$

Length of park = $\frac{4}{8}\ mile$

Let,

w be the width of park.

Area = Length * Width

$\frac{7}{8}=\frac{4}{8}w$

Multiplying both sides by $\frac{8}{4}$

$\frac{8}{4}*\frac{7}{8}=\frac{8}{4}*\frac{4}{8}w\\\frac{7}{4}=w\\w=\frac{7}{4}\ mile$

The width of park is $\frac{7}{4}$ miles.

Keywords: area, rectangles

Learn more about rectangles at:

#LearnwithBrainly

You might be interested in

Simply. If the solution is not a real number enter not a real number rotate picture answer all 3 please

yuradex [85]

Answer:

13. $\frac{\sqrt[5]{x^4} }{x}$ .

14. $v = \pm3\sqrt{5}$

15. 2.

Step-by-step explanation:

13. $x^{1/5} * x^{-2/5}$

= $x^{1/5 + (-2/5)}$

= $x^{1/5 - 2/5}$

= $x^{-1/5}$

= $\frac{1}{x^{1/5}}$

= $\frac{x^{4/5}}{x^{1/5 + 4/5}}$

= $\frac{x^{4/5}}{x}$

= $\frac{\sqrt[5]{x^4} }{x}$ .

14. $v^2 - 45 = 0$

$v^2 = 45$

$\sqrt{v^2} = \pm\sqrt{45}$

$\sqrt{v^2} = \pm\sqrt{3^2 * 5}$

$v = \pm3\sqrt{5}$ .

15. $\sqrt[3]{2} * \sqrt[3]{4}$

= $\sqrt[3]{2 * 4}$

= $\sqrt[3]{2 * 2 * 2}$

= $\sqrt[3]{2 ^3}$

= 2.

Hope this helps!

7 0

3 years ago

Match the correct word with it's definition

Hunter-Best [27]

Answer:

Rule by a small group : Oligarchy

Rule by Citizens : Democracy

Rule by No one Anarchy

Rule by king or Queen : Monarchy

6 0

3 years ago

Every Wednesday, Wayne works out for 3/4 of an hour at the fitness center. Every Saturday, he goes to the fitness center again a

matrenka [14]

3/4 of an hour = 45 minutes
45 * 3 = 135 minutes
135 + 45 = 180 minutes
He spends 180 minutes or 3 hours

4 0

3 years ago

Read 2 more answers

The following table shows the monthly charges for subscribing to the local newspaper.

Ostrovityanka [42]

D. independent -- Number of Months
dependent -- Total Cost

The dependent Variable depends on the independent variable so, as the number of months change, the total cost changes.

4 0

3 years ago

The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot

Katarina [22]

Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

5 0

3 years ago

Read 2 more answers