Let's say 
. Let's find point 
so that we can find 
.
- Leah walks 40 yards south.
- Leah walks 60 yards west.
- Leah walks 10 yards north.
- Leah walks 20 yards east.
We have found that 
.
Now think about this scenario visually. We started at the center of something, which we call point 
, and then started moving around until we got to point . We can then form line between the points. However, realize that we can actually make a triangle. Just think of one of the legs as part of the x-axis and the other leg as part of the y-axis.
We can find the length of these parts, which is simply the absolute value of the coordinates of point . It may be a little hard to think about, but essentially, we can form a triangle with sides that consist of part of the x-axis, part of the y-axis, and . We also know that the lengths of the legs are 40 and 30.
Since we are given the two lengths of the legs on the triangle and trying to find the length of the hypotenuse, we can use the Pythagorean Theorem. This states:
and 
are the lengths two legs of the triangle
is the length of the hypotenuse
Thus, substituting in our values, we find:
The length of is 50.
Answer:
Step-by-step explanation:
The pool are is divided into 4 separated shapes: 2 circular sections and 2 isosceles triangles. Basically, to calculate the whole area, we need to find the area of each section. Due to its symmetry, both triangles are equal, and both circular sections are also the same, so it would be enough to calculate 1 circular section and 1 triangle, then multiply it by 2.
<h3>Area of each triangle:</h3>
From the figure, we know that <em>b = 20ft </em>and <em>h = 25ft. </em>So, the area would be:
<h3>Area of each circular section:</h3>
From the figure, we know that 
and the radius is 
. So, the are would be calculated with this formula:
Replacing all values:
Remember that 
Therefore, 
Now, the total are of the figure is:
Therefore the area of the symmetrical pool is
Answer: equilateral
Step-by-step explanation:
Well a long number 1.0989010989011 thats what u get
