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postnew [5]
2 years ago
7

What is the prime factor of 8

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
5 0
Prime factor is a factor that is a prime number.
Prime factors of :
8 : 2 × 2 × 2. Also can be written as
{2}^{3}
12 : 2 × 2 × 3. Also can be written as
{2}^{2} \times 3

20 : 2 × 2 × 5. Also can be written as
{2}^{2} \times 5

30 : 2 × 3 × 5

56 : 2 × 2 × 2 ×7. Also can be written as
{2}^{3} \times 7

70 : 2 × 5 × 7

You can find all of them by using Factor Tree [ as shown in the picture] or Dividing by prime numbers.

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Which answer choice is a solution to the equation 0.5x + 3.5 = 6?
kirill [66]

Answer:

x=5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
3 years ago
Wyatt has 32 marbles in his collection. Twenty of his marbles are red, four are blue, and the
dmitriy555 [2]

Answer:

6 and 2/5

Step-by-step explanation:

20% of 32 is 6.4

4 0
3 years ago
9 minus 3 divided by 1/3 plus 1 (solve using B.O.D.M.A.S. procedure)
Citrus2011 [14]
9 - 3 ÷ 1/3 + 1
BODMAS says that the first thing we do in this is the division (D), so 3 ÷ 1/3 = 9
9 - 9 + 1
Now we do the addition, 9 + 1 = 10
9 - 10 = -1
So your final answer is -1, I hope this helps!
7 0
3 years ago
Find the length of the third side. If necessary, round to the nearest tenth.
Natali [406]

Where is the picture? Nothing is attached to your question.

7 0
3 years ago
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