1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dolphi86 [110]
3 years ago
8

PLEASE HELP IT’S TIMED

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

a = -

b = -

c = 9

d = 3

e = 3

f = 2

Step-by-step explanation:

First we will solve the expression:

\frac{3x}{2x-6}+\frac{9}{6-2x}

Solving:

First we will take negative sign common, then take LCM of denominator and simplify the expression.

=\frac{3x}{2x-6}+\frac{9}{\textbf{-}(2x-6)}\\=\frac{3x}{2x-6}+\frac{\textbf{-}9}{(2x-6)}\\Taking\:LCM\\=\frac{3x-\mathbf{9}}{2x-6}\\=\frac{\mathbf{3}(x-\mathbf{3})}{\mathbf{2}(x-3)}\\=\mathbf{\frac{3}{2}}

So, After solving we get:

a = -

b = -

c = 9

d = 3

e = 3

f = 2

You might be interested in
At age 25, to save for retirement, you decide to deposit $75 at the end of each month in an ira that pays 6.5% compounded monthl
Alex787 [66]
Let P= $75, r=0.0054166, n= 40. In the future worth formula, F= P((1+r)^(n-1) -1) / r, it would yield a future worth of 3,247.16 at the age of 65. And the interest rate is I= (r^n-10)/(r-1). It yields an interest of 1.033
4 0
4 years ago
About 5% of hourly paid workers in a regioner the prevailing minimum wage or less A grocery chain offers discount rates to compa
Fed [463]

Answer:

0

Step-by-step explanation:

Let X  to be a random variable that looks a binomial distribution which denoted the number of employees out of the 281 who earn the prevailing minimum wage or less

The sample size n = 281

The population parameter p = 5% = 0.05

Using normal approximation for the mean.

\mu = np

\mu = 281\times 0.05

\mu = 14.05

The standard deviation is:

\sigma = \sqrt{np(1-p)}

\sigma = \sqrt{281 \times 0.05(1-0.05)}

\sigma = \sqrt{281 \times 0.05(0.95)}

\sigma = \sqrt{13.3475}

\sigma =3.6534

By using continuity correction; the sample mean x is:

x = 30 - 0.5

x = 29.5

The z statistic test can now be as follows:

Z = \dfrac{x-\mu}{\sigma}

Z = \dfrac{29.5-14.05}{3.6534}

Z = \dfrac{15.45}{3.6534}

Z = 4.23

Thus, the probability that company A will get a discount is

P(X ≥ 30) = P(Z >4.23)

= 1 - P(Z < 4.23)

By using the Excel function for the z score 4.23 i.e. "=1 - NORMSDIST(4.23)" we get;

= 0.0000

7 0
3 years ago
What results only in horizontal compression of y=1/x by a factor of 6
murzikaleks [220]

I'm assuming you mean a compression of factor 6 

In that case, it will be h = 1/6x

4 0
4 years ago
Read 2 more answers
Simplifying 14 to the 0 power + 2 to the 7th power plus 15 to the 1 power?​
Maurinko [17]

Answer:

144

Step-by-step explanation:

1+128+15

144

5 0
3 years ago
Read 2 more answers
What is 8 rounded to the nearest hundred
marishachu [46]

Answer:

0

Since 8 is too small to be rounded to 100, it's rounded down to 0.

3 0
4 years ago
Other questions:
  • What value will make the equation the equation true -2.1- ? = -1 1/2
    13·1 answer
  • For every girl taking a martial arts school, there are 3 boys who are taking classes at the school. If there are 236 students ta
    8·1 answer
  • What is the volume of 22.5 g of metal with a density of 2.81 g/cm
    11·1 answer
  • How do I find the scale factor of this problem
    13·2 answers
  • The Bayside Bugle charges by the word to run automotive ads. The newspaper
    6·1 answer
  • At Southern States University​ (SSU) there are 399 students taking Finite Mathematics or Statistics. 238 are taking Finite​ Math
    10·1 answer
  • How do I solve this
    9·1 answer
  • Could you please help me if you know how to do this
    8·1 answer
  • 9<br>Reduce to its lowest term.<br>36/100​
    14·1 answer
  • 6b 4r represents the total cost of the rice and beans Gabriel bought. If he returns 2 bags of beans and 1 bag of rice, the expre
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!