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Amanda [17]
3 years ago
9

You are ordering concert tickets. You pay a processing of $5, plus $18 per ticket. How many tickets can you buy for $100?

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0
Well, first you subtract 5 from 100. Then you divide your answer by 18. You should 5.somethingsomething. But you can't buy .2 of a ticket. So your answer is 5 tickets
Liula [17]3 years ago
3 0
You could buy 4 tickets.
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A coin is pulled from a jar and then put back in the jar. If 40 coins are pulled, enter the number of times a nickel is expected
neonofarm [45]

Answer:

20 times

Step-by-step explanation:

40 divided by 2

4 0
3 years ago
The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
I'm not really good at it can you help. ?
Vesnalui [34]
Sure , What Do Youu Need Help With ?
5 0
3 years ago
Solve the equation<br> -18 + 24 = -2(x+6)
anzhelika [568]

Answer:

x = -9

Step-by-step explanation:

-18+24 = -2(x+6) Distribute and simplify

6 = -2x-12 Add 12 to both sides

18 = -2x Divide by -2 on both sides

-9 = x Here's your answer

Hope this helps! :D

3 0
2 years ago
Read 2 more answers
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