With the f(x) = x^2 - 2x + 1 there is an even degree polynomial as the highest degree here is 2 and there is a positive leading coefficient as the coefficient for the highest degree is considered to be 1. Therefore all statements for f(x) is false.
With g(x) = x^3 +1 there is an odd degree polynomial as x is raised to 3 and there is a positive leading coefficient as x^3 is multiplied to 1. Therefore only the fourth statement holds to be true
Grad point ?????!??????!!!!??
<h3>
Answer: C = -4</h3>
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Work Shown:
C(x+2) - (x+2)(x-2) = 0
(x+2)(C-(x-2)) = 0
(x+2)(C-x+2) = 0
x+2 = 0 or C-x+2 = 0
x = -2 or x = C+2
If we want one solution only, then we must make C+2 = -2 which solves to C = -4
If C = -4, then x = C+2 = -4+2 = -2 which matches with the first solution mentioned. If C is anything else but -4, then we'd have two different solutions (eg: C = 10 leads to x = C+2 = 12 as the other solution)
Answer:
Theres no equation here?
Step-by-step explanation:
At midnight, the tempertuare was 31.2 degrees below 0, and in the morning, it was 6.7 degrees below 0
