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Anarel [89]
2 years ago
15

Which ordered pairs are solutions to the inequality 3x-4y>5

Mathematics
1 answer:
Sloan [31]2 years ago
6 0

Note: you did not provide the answer options, so I am, in general, solving this query to solve your concept, which anyways would clear your concept.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

3x-4y>5

All we need is to find any random value of 'x' and then solve the inequality.

For example, putting x=3

3\left(3\right)-4y>5

9-4y>5

-4y>-4

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

\left(-4y\right)\left(-1\right)

4y

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4y}{4}

y

So, at x = 3, the calculation shows that the value of y must be less

than 1 i.e. y<1 in order to be the solution.

Let us take the random y value that is less than 1.

As y=0.9 < 1

so putting y=0.9 in the inequality

3\left(3\right)-4\left(0.9\right)

=9-3.6

=5.4

  • As 5.4 > 5

Means at x=3, and y=0.9, the inequality is satisfied.

Thus, (3, 0.9) is one of the many ordered pairs solutions to the inequality 3x-4y>5.

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