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amid [387]
2 years ago
14

a grandfather is 8 times older than his grand daughter. in 8 years the grandfather will be 5 times as older as his grand daughte

r. how old is each of then now NEED HELP ASAP
Mathematics
1 answer:
mash [69]2 years ago
6 0

Answer:

256 it's the answer

Step-by-step explanation:

HOPE THAT HELPS!!!!!!!!

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F(x)=-6(x+5) find the value of f(4) for the function
user100 [1]

Answer:

-54

Step-by-step explanation:

For this question, all you have to do it plug 4 in for x.

-6(4+5)

-6(9)

-54

5 0
2 years ago
Factor f(x) = (x³-x²)(3x+3)
Elenna [48]

Answer:

3x^2(x-1)(x+1)

Step-by-step explanation:

Can I have brainliest please?

8 0
3 years ago
Median of 3,17,17,11,8,13,5,18
-Dominant- [34]
I believe that the answer is 13
7 0
3 years ago
Read 2 more answers
What is the next number in the sequence? 3, 6, 12, , ... place an x by the pattern of the sequence. add 2 subtract 2 times 2?
ch4aika [34]
3,6,12...

this is a geometric sequence with a common ratio of 2. That means u multiply each term by 2 to find the next term.

start with 3
3 * 2 = 6
6 * 2 = 12
12 * 2 = 24...this would be ur next term

so ur answer is : multiply by 2
8 0
3 years ago
How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

__

You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

__

Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
2 years ago
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