Angle bisectors TX and UY triangle TUV meet at point I. Find all possible values of angleV if angleTIU = 109. As your answer, en
ter the number of degrees in angleV. If you find more than one possibility, list the possible values in increasing order, separated by commas.
1 answer:
Check the picture attached.
let m(VTI)= m(ITU)=a and let m(VUI)= m(IUT)=b
Then, in triangle TUV:
2a+2b+c=180°
2(a+b)+c=180°
c=180°-2(a+b)
In triangle TUI:
a+b+109°=180°
a+b=180°-109°=71°
substitute in c=180°-2(a+b):
c=180°-2(a+b)=180°-2*71°=180°-142°=38°
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