<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.
As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation
∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
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Step-by-step explanation:
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It would be an obtuse angle :)
Answer: A and C
Ecplanation: photo
Answer:
<u>The most simplified form is 15√10</u>
Step-by-step explanation:
1. Let's simplify the expression:
20√270 ÷ 4√3
20√9 * 30/ 4√3 (√270 = √9 * 30)
60 √30/ 4√3
(60 √3 * √10) / 4√3 (√30 = √3 * √10)
60/4 √10 ( We cancel √3 in the numerator and in the denominator)
15√10
<u>The most simplified form is 15√10</u>