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Tpy6a [65]
2 years ago
6

If you wanted to gather information about birth months and chronotypes, what kind of information would you look for?

Mathematics
1 answer:
PolarNik [594]2 years ago
3 0

Answer:

my birth months and cryptrones

Step-by-step explanation:

You might be interested in
A manufactured product has a length that is normally distributed with a mean of 12 cm. The product will be unusable if the lengt
Sav [38]

Answer:

a) σ  = 0,1612

b) P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

Step-by-step explanation:

NOTE: I assume the unusable length s 11,5 and less

a) For a normal distribution, the probability of P = 0,01 corresponds to z(score) =  -3,1 then:

- 3,1 = ( X - μ₀ ) / σ

- 3,1 = (11,5 - 12 )/ σ

-3,1 = - 0,5 / σ

σ  = 0,1612

b) If σ = 0,1612

P [ 11,75 < X < 12,35]

z₁ (score)  = ( 11,75 - 12 ) / 0,1612

z₁  = - 0,25/ 0,1612

z₁  = -1,55

From z table  P [ 11,75 < X] = 0,0606

z₂ (score) = ( 12,35 - 12) / 0,1612

z₂ = 0,35 / 01612

z₂ = 2,17

From z table  P [ X < 12,35] = 0,9850

Finally P [ 11,75 < X < 12,35] = 0,9850 -  0,0606

P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

5 0
3 years ago
Kennedy has a gross income of $95,000. What is her total tax due?
ki77a [65]
Total tax due Answer: $27,000.
3 0
2 years ago
A national survey interviewed 3800 people ages 18 and older nationwide by telephone. One question asked was the amount of gasoli
NeTakaya

Answer:

For this case a parameter represent the population data and for this case the parameter would be the true mean \mu who represent the amount of gasoline they used in the previous week

\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75

And the sample mean is an unbiased estimator of the true mean.

Step-by-step explanation:

For this case a parameter represent the population data and for this case the parameter would be the true mean \mu who represent the amount of gasoline they used in the previous week

And in order to estimate the parameter of interest we use a survey of n =3800 and the sample mean who represent an statistic is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we got:

\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75

And the sample mean is an unbiased estimator of the true mean.

4 0
3 years ago
Please help me this is due tomorrow thank you
marusya05 [52]

Answer:

The answer is option B.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Round yo the nearest hundred plz it’s not much!!!!!!!!!
natita [175]
A is the answer of not I’m sorry for that
7 0
3 years ago
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