If you wanted to gather information about birth months and chronotypes, what kind of information would you look for?

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

Answer:

my birth months and cryptrones

Step-by-step explanation:

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A manufactured product has a length that is normally distributed with a mean of 12 cm. The product will be unusable if the lengt

Sav [38]

Answer:

a) σ = 0,1612

b) P [ 11,75 < X < 12,35] = 0,92,44 or 92,44 %

Step-by-step explanation:

NOTE: I assume the unusable length s 11,5 and less

a) For a normal distribution, the probability of P = 0,01 corresponds to z(score) = -3,1 then:

- 3,1 = ( X - μ₀ ) / σ

- 3,1 = (11,5 - 12 )/ σ

-3,1 = - 0,5 / σ

σ = 0,1612

b) If σ = 0,1612

P [ 11,75 < X < 12,35]

z₁ (score) = ( 11,75 - 12 ) / 0,1612

z₁ = - 0,25/ 0,1612

z₁ = -1,55

From z table P [ 11,75 < X] = 0,0606

z₂ (score) = ( 12,35 - 12) / 0,1612

z₂ = 0,35 / 01612

z₂ = 2,17

From z table P [ X < 12,35] = 0,9850

Finally P [ 11,75 < X < 12,35] = 0,9850 - 0,0606

P [ 11,75 < X < 12,35] = 0,92,44 or 92,44 %

5 0

3 years ago

Kennedy has a gross income of $95,000. What is her total tax due?

ki77a [65]

Total tax due Answer: $27,000.

3 0

2 years ago

A national survey interviewed 3800 people ages 18 and older nationwide by telephone. One question asked was the amount of gasoli

NeTakaya

Answer:

For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

$\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75$

And the sample mean is an unbiased estimator of the true mean.

Step-by-step explanation:

For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

And in order to estimate the parameter of interest we use a survey of n =3800 and the sample mean who represent an statistic is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$