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mixer [17]
3 years ago
7

HEEEEEELLLPPPPPPPP!!!!!!!!!!!!

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0
The standard form would be y = 7x^2 - 42x + 67
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What is the value of the 3 in 63?
Rina8888 [55]

Answer:

ones

Step-by-step explanation:

63

6=60

3=3

so it is in the ones place

6 0
3 years ago
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Which of the following will form the composite function?
zhuklara [117]

Answer:

B

Step-by-step explanation:

In the composition of <em>f</em><em> </em>and <em>g</em>, the equation is telling us to place the function <em>f</em> inside <em>g</em>. Observing in B that <em>f</em> is (x + 4), then this can be put in place of the x in 3x^2, making it 3(x + 4)^2 and finally the minus 5.

5 0
3 years ago
PLS HELP WILL GIVE BRAINLIEST
Oduvanchick [21]

Answer:

60

The angle acute so my guess is 60

Hope this helps :)

6 0
3 years ago
Is 78.006 greater, less, or equal to 78.01
skad [1K]
Less, 78.01 has a one in the hundredths place, while 78.006 has a 0, and 0 < 1.
6 0
3 years ago
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(Laws of Exponents with Whole Number Exponents LC)
Karolina [17]

The given expression will be equal to ( 2.3 )¹⁵ / ( 0.9 )¹². The correct option is D.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given expression is 2.3 raised to the fifth power divided by 0.9 raised to the fourth power, all raised to the third power.

Write the expression in the mathematical form and solve:-

[ ( 2.9⁵) / ( 0.9 )⁴ ]³ = [ ( 2.9⁵) / ( 0.9 )⁴ ]³

                             =  [ ( 2.9 )¹⁵ / 0.9 )¹² ]

Therefore, the given expression will be equal to ( 2.3 )¹⁵ / ( 0.9 )¹². The correct option is D.

To know more about an expression follow

brainly.com/question/17800360

#SPJ2

8 0
2 years ago
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