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kogti [31]
3 years ago
12

9r-5r+2+r ????????? Pls help me

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

5r + 2

Step-by-step explanation:

9r-5r+2+r=5r+2

\mathrm{Group\:like\:terms}

=9r-5r+r+2

\mathrm{Add\:similar\:elements:}\:9r-5r+r=5r

=5r+2

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Work:  
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Write an equation of the line passing through the point (3, -1) and parallel to the line y=2/3x - 5. Show work
alex41 [277]

Answer:

The answer is: y = 2/3x - 3

Step-by-step explanation:

Given point: (3, -1)

Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.

Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:

y - y1 = m(x - x1)

y - (-1) = 2/3(x - 3)

y + 1 = 2/3x - 6/3

y + 1 = 2/3x - 2

y = 2/3x - 3

Proof:

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= 2 - 3

= -1, giving the point (3, -1)

Hope this helps! Have an Awesome Day!!  :-)

6 0
3 years ago
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