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Ymorist [56]
3 years ago
5

A differential equation is an equation involving an unknown function and its derivatives. Consider the differential equation 0.

a. Show that satisfies the equation for any constant A. b. Show that satisfies the equation for any constant B. c. Show that satisfies the equation for any constants A and B.
Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer: hi your question is poorly written below is the correct question

answer :

a) y1 = Asint,   y'1 = Acost  , y"1 = -Asint

b) y2 = Bcost,   y'2 = Bsint , y"2 = - Bcost

c) y = Asint + B cost satisfies the differential equation for any constant A and B

Step-by-step explanation:

y" + y = 0

Proves

a) y1 = Asint,   y'1 = Acost  , y"1 = -Asint

b) y2 = Bcost,   y'2 = Bsint , y"2 = - Bcost

c) y3 = y1 + y2 ,   y'3 = y'1 + y'2,  y"3 = y"1 + y"2

∴ y"1 + y1 = -Asint + Asint

  y"2 + y2 = -Bcost + Bcost

  y"3 - y3 = y"1 + y"2 - ( y1 + y2 )

               = y"1 - y1 + y"2 - y2  

               = -Asint - Asint  + ( - Bcost - Bcost )  = 0

Hence we can conclude that y = Asint + B cost satisfies the equation for any constant A and B

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Katen [24]

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Part A:- x +11 ft     Part B:- (4x+54)ft   part C:- x= 2ft  

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

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length and breadth of Trapdoor are (x+ \frac{1}{2} ) by 2x ft.

The Outside length of Rectangle is (x+16 ) ft.

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             x^{2} + 27x+ 176. Write an expression for the width of stage.

So,        Area of rectangle =  length \times breadth

                 x^{2} + 27x+ 176 = (x+16) \times breadth

                     Breadth = \frac{x^{2} + 27x+ 176}{x+16}

                     Breadth = x+11 ft.                       ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here,   Perimeter of Rectangle = 2(L+B)

                                                    = 2(x+16 + x +11)

                                                    = (4x + 54) ft

Part C:- The area of trapdoor is 10 ft^{2}. Find the value of x.

So,                        Area of trapdoor = 10 ft^{2}

                              (x +\frac{1}{2}) \times 2x =10 ft^{2}

                               2x^{2} +x - 10 = 0

                                  x = \frac{-1-9}{4} , \frac{-1+9}{4}

                                  x = \frac{-5}{2} , 2

Hence value of x is 2 ft             (Neglecting the negative value because                      

                                                   length cannot be negative).

Part D:-  The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So,   Length of trapdoor is (2+\frac{1}{2} ) = \frac{5}{2} ft

        breadth of trapdoor is 2\times 2 = 4ft

Now, outside length of Rectangle is = 18ft

And outside breadth of rectangle is = 13ft

Here, Area of trapdoor = \frac{5}{2} \times 4 = 10ft^{2}              ...................(2)

         Area of rectangle = 18 \times 13= 234 ft^{2}        ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

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