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Gwar [14]
3 years ago
15

B = 57°, b = 26 cm. Find c in cm. Round to 2 decimal places.​

Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

17

Step-by-step explanation:

Answer:

21.1cm

Step-by-step explanation:

From sine rule which can be expressed as

b/ sinB = c/sin C

B = 57°,

b = 26 cm.

FROM THE COMPLETE QUESTION,

C=43°

Then we can substitute this

26/sin(57) = c/sin(43)

If we cross multiply and make "c" subject of the formula

c=[26 × sin(43)]/ sin57

c= 21.1 cm

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Answer:

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Step-by-step explanation:

The given rational function is

f(x) =  \frac{x - 5}{ - 4x - 2}

Let

y =  \frac{x - 5}{ - 4x - 2}

Interchange x and y

x=  \frac{y- 5}{ - 4y - 2}

Cross multiply

x( - 4y - 2)= y- 5

Expand

- 4xy   - 2x= y- 5  \\ - 4xy  - y=  2x - 5 \\y( - 4x - 1)=  2x - 5

Solve for y;

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or

y= \frac{  5 - 2x }{ 4x  + 1}

Therefore

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

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Step-by-step explanation:

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Can anyone help me integrate :
worty [1.4K]
Rewrite the second factor in the numerator as

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Then in the entire integrand, set x+2=\sqrt3\sec t, so that \mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt. The integral is then equivalent to

\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt
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Note that by letting x+2=\sqrt3\sec t, we are enforcing an invertible substitution which would make it so that t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3} requires 0\le t or \dfrac\pi2. However, \tan t is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which \tan t>0 so that |\tan t|=\tan t. This allows us to write

=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt
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We can show pretty easily that

\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C
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which means the integral above becomes

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Back-substituting to get this in terms of x is a bit of a nightmare, but you'll find that, since t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}, we get

\sec t=\dfrac{x+2}{\sqrt3}
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The comparison 0.3 > 0.09 is true.

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Answer:

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Step-by-step explanation:

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