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Nataliya [291]
3 years ago
10

A rectangular swimming pool is 8 ft deep. One side of the pool is 2.5 times longer than the other. The amount of water needed to

fill the swimming pool is 2880 cubic feet. Find the dimensions of the pool.
Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

First dimension= 12ft Second dimension= 12×2.5=30ft

Step-by-step explanation:

From the question, I was able to deduce that the swimming pool is a cuboid, and the formula for finding the volume of a cuboid is Length×Breadth×Height.

let the first dimension be the length and the second dimension be the breadth.

Therefore, the length=L , Breadth= 2.5×L= 2.5L and Height= 8ft. L×2.5L×8 = 2880 cubic feet.

2.5L²×8= 2880 cubic feet. Therefore, L²= 2880/(2.5×8)=144. L²=144. L=√144. L=12ft. and breadth= 2.5×Length= 2.5×12ft=30ft.

In a nutshell the first dimension is 12ft, and the second is 30ft.

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In the diagram, AD=CD=CB and measure of angle A=40°. How many degrees are in angle DCB?​
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Answer:

20^{\circ}

Step-by-step explanation:

Consider triangle ACD. This triangle is isosceles triangle, because AD = DC. Angles adjacent to the base AC are congruent abgles, so

m\angle DAC=m\angle DCA=40^{\circ}

The sum of the measures of all interiror angles in the triangle is always 180^{\circ}, then

m\angle DAC+m\angle DCA+m\angle ADC=180^{\circ}\\ \\40^{\circ}+40^{\circ}+m\angle ADC=180^{\circ}\\ \\m\angle ADC=180^{\circ}-40^{\circ}-40^{\circ}=100^{\circ}

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m\angle BDC=m\angle DBC=80^{\circ}

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m\angle DBC+m\angle BDC+m\angle BCD=180^{\circ}\\ \\80^{\circ}+80^{\circ}+m\angle BCD=180^{\circ}\\ \\m\angle BCD=180^{\circ}-80^{\circ}-80^{\circ}=20^{\circ}

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3 years ago
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