Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
Answer:b=4
Step-by-step explanation:
Answer:
A ) subtract the second equation from the first equation
Step-by-step explanation:
2x + 3y = 7
2x - 4y = -5
subtracting the second equation from the first equation we get,
7y = 12
y=12/7
This is the correct option
Answer:
A line....
Step-by-step explanation:
Plz be more clear with your question!
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