In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
You answer is: 17
Or otherwise B. is your correct answer.
(9 - 23) = -(14)
| 47 - 16| = 31
31 + (-14) = 17
Answer:
todays my birthday
Step-by-step explanation:
Answer:
89
Step-by-step explanation:
To find the area of the rectangle, you do 13 times 8. That gives you 104. Now, for the triangle, you do 1/2 base times height. That is 1/2 of (13 - (4 + 4)) times 6. That equals 1/2 of 5 times 6. So 5 times 3 is 15. 104 - 15 is 89. I hope this helped and please mark me brainliest! Thanks.
P=x+38
add all individual sides together (is also the perimeter):
p=(x+3)+(x-5)+x+(x-2)+(x-4)+(x-1)+(x-1)
=7x-10
set both p equal:
x+38=7x-10
38=6x-10
48=6x
8=x
then insert x=8 in all the side/perimeter equations:
p=x+38=8+38=46
sides:
x=8
x-2=8-2=6
x-1=8-1=7
x-4=8-4=4
x-5=8-5=3
x+3=8+3=11
