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Tcecarenko [31]
2 years ago
7

Solve 7z^2 + 4z - 1) + (2z^2 - 6z + 2)

Mathematics
1 answer:
Vlad1618 [11]2 years ago
5 0

Answer:

9z^2+4x+1

Step-by-step explanation:

Remove parentheses.

7{x}^{2}+4x-1+2{x}^{2}+2

7x  

2

+4x−1+2x  

2

+2

2 Collect like terms.

(7{x}^{2}+2{x}^{2})+4x+(-1+2)

(7x  

2

+2x  

2

)+4x+(−1+2)

3 Simplify.

9{x}^{2}+4x+1

9x  

2

+4x+1

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The stock of Company A gained 2% today to $79.56. What was the opening price of the stock in the beginning of the day?
CaHeK987 [17]

Answer: $78

Step-by-step explanation:

From the question, we are informed that the stock of Company A gained 2% today to $79.56. The opening price of the stock in the beginning of the day will be calculated as:

= [100% / (100% + 2%)] × 79.56

= (100% / 102%) × 79.56

= 1/1.02 × 79.56

= 79.56/1.02

= 78

Therefore, opening price of the stock in the beginning of the day is $78

5 0
3 years ago
85 divided by 3.5 i need to know
labwork [276]

24.28571429

or rounded 24.29



4 0
3 years ago
Read 2 more answers
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

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