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2 years ago

How much sand do you need to fill this box?

Mathematics

2 answers:

LenaWriter [7]2 years ago

6 0

V = L x W x H
V = 5 x 2 x 3
V = 30 ft

ANSWER: you need 30ft of sand to fill the box

GenaCL600 [577]2 years ago

3 0

Answer:

30ft

Step-by-step explanation:

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How do you find direct variation? im having trouble understanding this subject

rodikova [14]

I was too just a couple of weeks ago. So direct variation is the constant way to variables change together. EX:
x y
1 2
2 4
3 6
Direct variation must be in the format b=ka where k is a constant. So the direct variation here could be y=2x. Understand?

5 0

3 years ago

Gina takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit

Kipish [7]

Answer: second option.

Step-by-step explanation:

Let be "w" the credit hours at Westside Gina is taking.

You know that class fees are $98 per credit hour at Westside, then the expression for the dollar amount she paid for her class fees at Westside is:

$98w$

Since she is taking a combined total of 13 credit hours at the two schools, the credit hours at Pinewood Gina is taking can be represented by this expression:

$13-w$

You know that class fees are $115 per credit hour at Pinewood, then the dollar amount she paid for her class fees at Pinewood can be expressed as:

$115(13-w)$

Therefore, the expression for the combined total dollar amount she paid for her class fees is:

$total\ paid=98w+115(13-w)\\\\total\ paid= -17w + 1495$

6 0

2 years ago

Read 2 more answers

Write the equation of the line in slope intercept form that goes through points (1,8) and (5,20)

pantera1 [17]

Answer:

y=3x+5

Step-by-step explanation:

Point slope equation:

y=mx+b

m-slope, b- is y-intercept

equation given 2 points

y-y1 = m(x-x1)

For point (1,8) and slope m=(y2-y1)/(x2-x1) = 20-8/5-1=12/4=3

y-8 =3(x-1)

arange it in point slope format

y-8=3x-3

y=3x-3+8

y=3x+5

6 0

3 years ago

Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$

Now, put the value of length(2B) into equation 3 to know length (1B)

$length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm$

I really hope this helps you, have a great day.

6 0

2 years ago

A right triangle ABC with right angle at B and base BC is drawn. Length of AB is 12, length of BC is 11.5. A similar right trian

expeople1 [14]

Answer:

Option D is correct.

Length of PQ is 36 unit.

Explanation:

If the measures of two sides in one triangle are proportional to the corresponding sides in the another triangle and their including angles are congruent, then the triangles are similar.

Given: Right angle triangle ABC at B , Length of AB = 12 unit and length of BC = 11.5 unit and in right angle triangle PQR at Q , length of QR = 34.5 unit.

Also it is given that Angle A is congruent to angle P and angle C is congruent to angle R.

To find the length of QR:

It is given that ΔABC and ΔPQR are Similar triangle

then, by the definition of similar triangle:

$\frac{PQ}{AB} = \frac{QR}{BC}$