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Alina [70]
1 year ago
7

Which expression is equivalent to the area of square A, in square inches?

Mathematics
1 answer:
mezya [45]1 year ago
7 0

Answer:

the required expression equivalent to the area of the square A in inches is (10² + 24²).

Step-by-step explanation:

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What is the estimate of 405?
mario62 [17]

Answer:

400


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
16) Your salary goes from $8.75 an hour at your present job to $16.50 an hour in your new job. What is
Agata [3.3K]

Answer:

The percent change in salary from one job to the next is 88.57%.

Step-by-step explanation:

The previous salary of per hour =  $8.75 per hour

The current salary of per hour  = $16.50 per hour

Change in the salary rate per hour  =  Current salary  -  Previous Salary

                                                             = $16.50 per hour -  $8.75 per hour

                                                             =$7.75 per hour

⇒The change in the salary per hour rate is $7.75

Now, \textrm{Percentage Change in salary}  = \frac{\textrm{Change in the rate of salary}}{\textrm{Previous Salary}}  \times 100

= \frac{7.75}{8.75}  \times 100 = 88.57

or, the change in salary percentage is 88.57%

Hence, the percent change in salary from one job to the next is 88.57%.

4 0
3 years ago
(3cosx-4sinx) + (3sinx+4cosx) = 5
Ksenya-84 [330]
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º      (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when  0≤x≤360º are:  36.87º and 306.87º.


3 0
2 years ago
Jim makes the chart shown below to prove that Triangle APD is congruent to triangle BPC:
Oliga [24]

Answer:

Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.

From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.


Therefore, the justification to complete Jim's proof is "SAS postulate"



Step-by-step explanation:


6 0
2 years ago
For the past four weeks, Micah has been recording the daily high temperature. During that time, the high temperature has been gr
Artyom0805 [142]
The same:
20/28 = 5/7
4 0
2 years ago
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