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2 years ago

Which expression is equivalent to the area of square A, in square inches?

Mathematics

1 answer:

mezya [45]2 years ago

7 0

Answer:

the required expression equivalent to the area of the square A in inches is (10² + 24²).

Step-by-step explanation:

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Solve the system of equations graphicallySolution=?

BigorU [14]

The given system is

$\begin{cases}y=\frac{5}{2}x-8 \\ y=-\frac{1}{2}x-2\end{cases}$

Given that y = y, let's combine the equations

$\frac{5}{2}x-8=-\frac{1}{2}x-2$

Let's solve for x

$\begin{gathered} \frac{5}{2}x+\frac{1}{2}x=8-2 \\ \frac{6}{2}x=6 \\ 3x=6 \\ x=\frac{6}{3} \\ x=2 \end{gathered}$

Then, we find y

$y=-\frac{1}{2}x-2=-\frac{1}{2}\cdot2-2=-1-2=-3$

The solution is (2, -3).

The image below shows the solution graphically.

3 0

1 year ago

the mean of four consecutive even numbers is 15.the greatest of these numbers is a1.the least of these numbers is a2.

Lady bird [3.3K]

Hello,

I suppose you want the 4 numbers.

Let's call the numbers $2n,2n+2,2n+4,2n+6$
$2n+2n+2+2n+4+2n+6[=8n+12=15*4\\
8n+12=60\\
8n=48\\
n=6\\\\
2n=12\\
2n+2=14\\
2n+4=16\\
2n+6=18\\
$

7 0

3 years ago

Read 2 more answers

credit cards place a three-digit security code on the back of cards.what is the probability that a code starts with the number 7

Andrew [12]

So the numbers on the credit card can start with any single-digit number

So it could start with;
0
1
2
3
4
5
6
7
8
Or 9

We are looking for the odds of it starting with a 7

There is only one 7, so the numerator is 1
There are then nine other possible numbers it could be, and counting the number 7, there is a total of ten different possibilities, so 10 is the denominator

So the odds of the card starting with a 7 is
1/10

5 0

3 years ago

Solve -2x + 6 = -20. -7 -13 7 13

attashe74 [19]

Answer:

Step-by-step explanation:

-2x + 6 = -20

Step 1 subtract 6 from both sides

6 - 6 cancels out

-20 - 6 = -26

We now have -2x = -26

Step 2 divide both sides by -2

-2x/-2 = x

-26/-2 = 13

We're left with x = 13

6 0

3 years ago

Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio

Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that $p = 0.8$

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is $P(X \geq 1)$ when $n = 2$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96$

0.96 = 96% probability that at least one of them detect an enemy attack.

6 0

3 years ago