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Genrish500 [490]
3 years ago
7

50% of Brady's Halloween candy has been eaten. He has 68 pieces left. How much did he have​

Mathematics
2 answers:
artcher [175]3 years ago
7 0

Answer:

136

Step-by-step explanation:

Brady has eaten 50% of the original amount.  The final amount is 68.  So think, what 50% of a number is equal to 68?

Let x= original amount

Let n= final amount

n=68

50%= 0.5

0.5(x)= n

Divide both sides by 0.5

x= n/0.5, we know n=68, sub in 68 for n

x= 68/0.5

x= 136

Therefore, Brady had 136 pieces originally.

love history [14]3 years ago
5 0
136 pieces? Because 68 is half of it (50%) and 68 times 2 is 136
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The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
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Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

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xy=200

Hence from A we get

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Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

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y=\frac{2+\sqrt{4+400}{2}

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y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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