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3 years ago

Graph to answers i put

Mathematics

1 answer:

maksim [4K]3 years ago

5 0

Answer:

The domain of f is {x : x ∈ R, -7 ≤ x ≤ 7} ⇒ [-7, 7]

Step-by-step explanation:

The domain of a function is all the values of x make the function defined

In the given graph

∵ The graph drawn from x = -7 to x = 7 and from y = -6 to y = 4

→ That means the values of x started from -7 and ended at x = 7

∵ The coordinates of the starting point of the graph of f are (-7, -5)

∵ The coordinates of the ending point of the graph of f are (7, 3)

∴ -7 ≤ x ≤ 7

∵ Values of x are the domain of the function

∴ The domain of the function is -7 ≤ x ≤ 7

∴ The domain of f = {x : x ∈ R, -7 ≤ x ≤ 7} ⇒ [-7, 7]

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3 years ago

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3 years ago

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

ad-work [718]

<h3>Conner work is correct. Jana work is wrong</h3>

Solution:

Given that,

Conner and Jana are multiplying:

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

Given Jana's work is:

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0

3 years ago

A company provided the following data: Selling price per unit: 60 Variable cost per unit 20 Total fixed costs 400,000 HOw many u

EastWind [94]

Answer:

The company needs to sell 9000 units in order to turn a profit of $40,000

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

From the question we can get some important hints before creating our formula. First the Selling Price will be profit so it will be a positive number, but both unit cost and fixed costs are losses so they will be negative values in our formula. Also our formula will depend on the amount sold which we can represent as the variable x. With these hints we can create our formula as the following

$(60x-20x)-400,000 = y$

Where:

x is the amount of units created and sold
y is the total profit after selling x-units

Now that we have our formula the question asks how many units need to be sold in order to earn a profit of $40,000. We can calculate this by replacing the $40,000 with y and solving for x like so,

$(60x-20x)-400,000 = 40,000$ .... add 400,000 on both sides