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mariarad [96]
3 years ago
6

Please please help it is very urgent!​

Mathematics
1 answer:
Liula [17]3 years ago
7 0
Y = -0.33x + -5.00 (rounded to the nearest 100)
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Solve the following equation for X: 3+1/x
vladimir2022 [97]

Answer:

x=2

......

Step-by-step explanation:

x=3+1/x

x^2=4

x=2

6 0
3 years ago
Pl help it’s for a grade
Otrada [13]

Answer:

The initial fee

Step-by-step explanation:

Thats the fee to sort of set up the membership, the 15 is the monthly cost, and m is the months you use the membership. Make sense?

5 0
3 years ago
Are these ordered pairs in direct variation (1 2) (2 3) (3 4)
OlgaM077 [116]
Yes, Because if you draw this into a graph it comes has a straight line going thought the origin
4 0
4 years ago
Read 2 more answers
Xy + w = 9
Alexandra [31]

xy + w = 9

xy = 9 - w

y = ( 9 - w ) / x


x ( 4 - k ) = p

4 - k = p/x

- k = (p - 4) / x

k = - (p - 4)/x

7 0
3 years ago
A scrap metal dealer claims that the mean of his sales is "no more than $80," but an Internal Revenue Service agent believes the
Artyom0805 [142]

Answer:

There is enough not evident to support dealer's claim that his sales is no more than $80.                              

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = $80

Sample mean, \bar{x} = $91

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = $21

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 80\text{ dollars}\\H_A: \mu > 80\text{ dollard}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{91 - 80}{\frac{21}{\sqrt{20}} } = 2.3425

Now, t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = 1.729

Since,                        

The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

There is enough not evident to support dealer's claim that his sales is no more than $80.

4 0
3 years ago
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