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3 years ago

Consider all numbers consisting of four different digits all between 1 and 9 . How many of these are odd

Mathematics

1 answer:

Slav-nsk [51]3 years ago

7 0

Answer:

1680

Step-by-step explanation:

Considering repeatition is not allowed.

We can use permutation to reach to the required answer.

Consider four digits to be placed in four boxes. Now for the number to be odd, unit digit must be odd. Therefore, unit digit can only be filled by 1, 3, 5,7, or 9. That is 5 ways. Now, other three boxes can be filled with 8, 7 and 6 ways respectively.

Therefore, Total numbers = 5×8×7×6 = 1680

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Given condition is:

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Which expression shows how to multiply 5x381 by using place value and exxpanded form?

Dovator [93]

<span><span>1. </span>We have the given number = 5 x 381
Let’s show how to multiply this given equation using its expanded form and place value
=> 5 x 381
since we’re multiplying, we will start with the ones value which is 1
=> 5 x 1 = 5
Second is on the tens value
=> 5 x 80 = 400
Third is the hundreds value
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Now, we already have the answer to each values. Add
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3 years ago

the case of napkins contained 45 packs with a total of 10,125 napkins. each napkin contained the same number of napkins. write a

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You would need to do 10,125/45 = n, and in which case we just solve.
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Hope this helps and have a nice day:)

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3 years ago

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(-1,1)

(1,-1)

(2,-2)

(-2,2)

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Option D is correct

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3 years ago