Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
I found the accompanying picture of this word problem.
The circle was inscribe in the triangle. The area outside of the circle but inside the triangle is the shaded area.
True. The shaded area of the following shape can be found by subtracting the area of the circle from the area of the triangle.
Answer:
i - 6d/0.5
that's all i remember ive done this before but my memory is wack, im sorry
Answer:
31°
Step-by-step explanation:
Transversal BD crosses parallel lines AB and CD, creating alternate interior angles ∠2 and ∠5. As you know, alternate interior angles are congruent, so have the same measure.
m∠5 = m∠2 = 31°
After solving 
we get 
So, Option A is correct.
Step-by-step explanation:
We need to solve the expression:
For solving, we apply the rule that:
if |u| ≥ a and a > 0 then, u ≤ -a and u ≥ a
Applying the rule:
After solving we get
So, Option A is correct.
Keywords: Absolute rule
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