In this situation triangle BOC is inscribed in the circle. Length of BC is 10,91, length of BO is 5 (radius) and length of CO is 5 (radius).
we need to know theorem of sines:
Distribute
(x-3)(x+9)=-27
x^2+6x-27=-27
add 27 to both sides
x^2+6x=0
factor out x
x(x+6)=0
set each to zero
x=0
x+6=0
x=-6
x=0 and or -6
x=-6 or 0
Answer:
The two equations are not equivalent and no property is used.
Step-by-step explanation:
54 - (30 - 8) ... (i)
(54 - 30) - 8 ... (ii)
Solving (i) and applying PEMDAS:
We open the brackets first;
54 - 30 + 8 = 54 + 8 - 30 = 32
Solving (ii) and applying PEMDAS:
We open the brackets first;
54 - 30 = 24
24 - 8 = 16
Answer: X = 4
Step-by-step explanation: To solve for k in this equation, we want to get k by itself on the left side of the equation.
Since k is being multiplied by 5, to get k by itself, we need to divide by 5 on the left side of the equation. Since we divided by 5 on the left side, we must also divide by 5 on the right side.
On the left side, notice that the 5's cancel out, so we are simply left with z. On the right side, we have 20 divided by 5 which gives us 4.
Now we have X = 4.
Finally, remember to check your answer by substituting a 4 back into the original equation.
So we have 5 (4) = 20 which is a true statement.
This means that our answer, x = 4 is correct.
