part of the whole painting is gold colored.
<u>Solution:</u>
Given that , In art class, Arthur has created a triangle painting 
of his painting is purple.
He decided he wants to Paint 
of the purple area gold
We have to find what fraction of the whole painting will be painting?
Now, part of whole painting is purple
And, part of the purple area is gold ⇒ part of the part of whole painting is gold
Hence, part of the whole painting is gold colored.
Answer:
For f(x) = 2x + 3 and g(x) = -x 2 + 1, find the composite function defined by (f o g)(x)
(f o g)(x) = f(g(x))
= 2 (g(x)) + 3
= 2( -x 2 + 1 ) + 3
= - 2 x 2 + 5 Given f(2) = 3, g(3) = 2, f(3) = 4 and g(2) = 5, evaluate (f o g)(3)
Step-by-step explanation:
Answer:
- angle at A: 51°
- base angles: 64.5°
Step-by-step explanation:
The measure of the inscribed angle BAC is half the measure of the intercepted arc BC, so is 102°/2 = 51°.
The base angles at B and C are the complement of half this value, or ...
90° -(51°/2) = 64.5°
The angle measures in the triangle are ...
∠A = 51°
∠B = ∠C = 64.5°
18.386 rounded to the nearest hundredth would be 18.39
This is easy to do because you can factor
example
6/2=3 because 6=2*3 so 6/2=3/1 times 2/2 or 3
2x^3+17x^2+23x-42 can be factored out to equal
(x-1)(x+6)(2x+7)
so [(x-1)(x+6)(2x+7)]/(2x+7)=[(x-1)(x+6)] times (2x+7)/(2x+7)=(x-1)(x+6)=x^2+5x-6
the answer is (x-1)(x+6) or x^2+5x-6
