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Shtirlitz [24]
3 years ago
11

A baseball is thrown from the top of a building and falls to the ground below. The height of the baseball above the ground is ap

proximated by the relation h = -5t2 + 10t + 15, where h is the height above the ground in metres and t is the elapsed time in seconds. Determine the maximum height that is reached by the ball.
Mathematics
1 answer:
lidiya [134]3 years ago
5 0
Kstsskts stsxaeUzt. awyararka euaya
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Here are the vertices of rectangle FROG: (-2,5),(-2,1),(6,5),(6,1). Find the perimeter of this rectangle. If you get stuck, try
ryzh [129]

Answer:

Part 1) The perimeter of rectangle is equal to 24 units

Part 2) The area of rectangle is equal to 32 square units

Step-by-step explanation:

Part 1) Find the perimeter of rectangle

we know that

The perimeter of rectangle is equal to

P=2(L+W)

where

L is the length of rectangle

W is the width of rectangle

we have

F(-2,5),R(-2,1),O(6,1),G(6,5)

Plot the figure to better understand the problem

using a graphing tool

see the attached figure

Remember that in a rectangle opposite sides are congruent and the measure of each interior angle is equal to 90 degrees

so

FG=RO=L\\RF=OG=W

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance FG

F(-2,5),G(6,5)

substitute the values

d=\sqrt{(5-5)^{2}+(6+2)^{2}}

d=\sqrt{(0)^{2}+(8)^{2}}

FG=8\ units

step 2

Find the distance RF

R(-2,1),F(-2,5)

substitute the values

d=\sqrt{(5-1)^{2}+(-2+2)^{2}}

d=\sqrt{(4)^{2}+(0)^{2}}

RF=4\ units

step 3

Find the perimeter

P=2(L+W)

we have

FG=RO=L=8\ units\\RF=OG=W=4\ units

substitute

P=2(8+4)=24\ units

Part 2) Find the area of rectangle FROG

we know that

The area of rectangle is equal to

A=LW

we have

FG=RO=L=8\ units\\RF=OG=W=4\ units

substitute

A=(8)(4)=32\ units^2

8 0
3 years ago
Find the area of the composite figure
Pavlova-9 [17]

Answer:

45

Step-by-step explanation:

4 0
3 years ago
Evaluate the expression Arcsec(sqrt 2). Do not use your calculator to answer this question. Do not express answer in decimals.
Igoryamba
Pi/4 radians  
You're looking for the angle that has a secant of sqrt(2). And since the secant is simply the reciprocal of the cosine, let's take a look at that.
 sqrt(2) = 1/x
 x*sqrt(2) = 1
 x = 1/sqrt(2)
 Let's multiply both numerator and denominator by sqrt(2), so
 x = sqrt(2)/2 
 And the value sqrt(2)/2 should be immediately obvious to you as a trig identity. Namely, that's the cosine of a 45 degree angle. Now for the issue of how to actually give you your answer. There's no need for decimals to express 45 degrees, so that caveat in the question doesn't make any sense unless you're measuring angles in radians. So let's convert 45 degrees to radians. A full circle has 360 degrees, or 2*pi radians. So:
 45 * (2*pi)/360 = 90*pi/360 = pi/4 
 So your answer is pi/4 radians.
5 0
3 years ago
Read 2 more answers
The listed price of the video game was $34, but the price with tax came to $37.40. Find the percent sales tax.
Katarina [22]

Answer:

10%

Step-by-step explanation:

we want to find what % of 34 is 37.40

so, we will use the following equation:

\frac{part}{whole} = \frac{percent}{100}

for this scenario:

part = 37.40

whole = 34

percent = x

now plug in:

\frac{37.40}{34} = \frac{x}{100}                         cross multiply

34x = (37.40)(100)

34x = 3740                      divide both sides by 34

x = 110%

now we know that with tax, we paid 110% of the video game's price

110 - 100 = 10%

so the percent sales tax is 10%

<u>just to check... </u>

34 • 1.10 = $37.40

or

34 • .10 = 3.40

34 + 3.40 = 37.40

8 0
3 years ago
Lines are drawn on the gym floor for different sports for basketball playing area is marked so that there is an out of bounds. 2
choli [55]

Answer:

16 m  × 11 m

Step-by-step explanation:

The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.

The original length of gym = 20 m and original width of gym = 15 m

2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:

Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m

Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m

Therefore the dimensions of the basketball court is:

16 m × 11 m

7 0
3 years ago
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