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Mkey [24]
3 years ago
14

I need help now assssssap

Mathematics
2 answers:
Andreyy893 years ago
7 0

Answer:

assssssssssssssap

Step-by-step explanation:

  °   •  .°•    ✯

  °   •  .°•    ✯   ★ *     °      °·                            

  °   •  .°•    ✯   ★ *     °      °·                             .   • ° ★ •  ☄

  °   •  .°•    ✯   ★ *     °      °·                             .   • ° ★ •  ☄▁▂▃▄▅▆▇▇▆▅▄▃▁▂

Anit [1.1K]3 years ago
5 0
Yo yo yo What’s popping
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This is not 10 points and which question to answer

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HELPPP IK IT IS NOT MATHHHH PLZ
allochka39001 [22]

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Step-by-step explanation:

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A metal rod is 25.000cm long at 25.0 degrees Celsius. When heated to 102.0 degrees Celsius, it is 25.054 cm long. What is the co
inn [45]
<span>You may deduce what it represents by analyzing the formula you just wrote.
Well, </span>the coefficient of linear expansion as the fractional change in length per degree of temperature change. 

ΔL = c x L(initial) x ΔT 

where c is the coefficient of linear expansion. You can rewrite the equation to give you c. 

c = ΔL / [L(initial) x ΔT] 

<span>Just substitute the variables and the answer will be
c = 0.000028. </span>

Now, what it represents.It may represent the extent to which the rod expands with temperature when compared to its original length. 
6 0
4 years ago
Read 2 more answers
X² + y² = 34<br>x + y =8​
Nataly [62]

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  = 34 \\ x + y = 8 \\ x = 8 - y \\ substitute \: x \: in \\  {x}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4)}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4) }^{2}  =  {y}^{2}  - 16y + 64 \\   {y}^{2}  - 16y + 64 +  {y}^{2}  = 34 \\  {2y}^{2}  - 16y + 64 = 34 \\ {2y}^{2}  - 16y + 64  - 34 = 0 \\  {2y}^{2}  - 16y + 30 = 0 \\ 2 {y}^{2}  - 6y - 10y + 30 = 0 \\ (2 {y}^{2}  - 6y) - (10y + 30) = 0 \\ 2y(y - 3) - 10(y - 3) = 0 \\ (2y - 10)(y - 3) \\ 2y = 10 \\ y  = \frac{10}{2}  \\ y = 5 \\ or \\ y = 3 \\ if \: y = 5 \:  \: x = 3 \\ if \: y = 3 \:  \:  x = 5

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3 years ago
HELLLLLLLLLLLPPPPPPPPPPPPPP PLZ
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Its ok buddy your answer is C
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3 years ago
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