Which other expression has the same value as (-14)-(-8)

Which function forms an arithmetic sequence when x = 1, 2, 3, ...?

natka813 [3]

The first one is arithmetic sequence as each term decreases by same amount
(1/3) as x = 1,2,3,4...

5 0

3 years ago

In which number is the value represented by the digit 9 equal to 1/10 of the value represented by the digit 9 in the number 73,9

marshall27 [118]

Answer: 90

Step-by-step explanation:

In the number 73,951, the digit 9 is on the third position, so you need to put the number of the position minus one zeros before it: ( position number 3, 3 - 1 = 2, so we put 2 zeros)

the 9 in that digit represents a 900.

now, 1/10 times that number is:

900*(1/10) = 900/10 = 90

then the answer is 90.

In the number 90, the value represented by the 9 is equal to 1./10 times the value represented by the 9 in 73,951

3 0

3 years ago

A nation has five types of coins: sinds, dalts, lorgs, harps, and plunks.

USPshnik [31]

<h3>Answer: d) plunk</h3>

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Work Shown:

When comparing units like inches, feet and yards, we need to get everything in the same unit to make a valid comparison. So we'd need to convert everything to inches for instance. The same idea applies to these five coins. We need to get everything in either lorgs, sinds, plunks, harps or dalts (pick one of those five).

It's effectively the same as trying to convert dollars into cents (eg: $1.37 converts to 137 cents). Or you can think of it as 1 dollar = 100 cents, 1 quarter = 25 cents, 1 dime = 10 cents, and so on.

The steps in the various sections below will aim to get all the coins converted to lorgs as our base unit. I found the lorg coin to be the smallest of value through trial and error, which is why I'm aiming to get everything in terms of lorgs.

The four given equations are

1 sind = 4 lorgs
2 plunks = 5 dalts
5 sinds = 2 harps
1 plunk = 3 harps

I'll refer to them as equation (1) through equation (4) in that order above.

--------------

1 sind = 4 logs .... equation (1)

5 sinds = 20 lorgs .... multiply both sides by 5

2 harps = 20 lorgs .... replace "5 sinds" with "2 harps" from equation (3)

1 harp = 10 lorgs .... divide both sides by 2; call this equation (5)

--------------

1 plunk = 3 harps .... equation (4)

1 plunk = 3*(1 harp)

1 plunk = 3*(10 lorgs) .... plug in equation (5)

1 plunk = 30 lorgs .... call this equation (6)

---------------

2 plunks = 5 dalts ..... equation (2)

5 dalts = 2 plunks

5 dalts = 2*(1 plunk)

5 dalts = 2*(30 lorgs) .... replace 1 plunk with 30 lorgs; see equation (6)

5 dalts = 60 lorgs

1 dalt = 12 lorgs ..... divide both sides by 5; call this equation (7)

----------------

We found the following conversions:

1 sind = 4 lorgs .... given as equation (1)
1 dalt = 12 lorgs .... found earlier as equation (7)
1 harp = 10 lorgs .... equation (5)
1 plunk = 30 lorgs .... equation (6)

Each of those equations helps us see how much the value of the coins sind, dalt, harp, plunk are in terms of lorgs.

We can see that 1 plunk yields the most lorgs at 30. So the plunk coin is the most valuable. The lorg coin is least value since you need 4 of those coins to make the second lowest coin of 1 sind.

The order of the coins value from least to greatest is: lorg, sind, harp, dalt, plunk.

5 0

3 years ago

Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she

Anarel [89]

Answer:

$P(3.25 < \bar X < 4.25)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\sigma_{\bar X}}$

And using the z score we have:

$P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)$

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

$P(-1.667< Z< 0.833)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the time it takes her to complete one review, and for this case we know the distribution for X is given by:

$X \sim N(4,1.2)$

Where $\mu=4$ and $\sigma=1.2$

And we select a sample size of n =16. Since the dsitribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by: