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Genrish500 [490]
3 years ago
6

Please tell me the answer.

Mathematics
1 answer:
olchik [2.2K]3 years ago
7 0
X = 30



3x-5=x+55

2x=60

x=30
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This is a tough one that I solved, I wanted to see how everyone else solves it.
V125BC [204]

a=2c+40 z=2c+142 x=2c+165 b=c+82 y=c-20

14+2c+40+2c+142+2c+165+c+82+c-20=1203

c=86 2/3

y=66 2/3

b=168 2/3

x=338 1/3

z=315 1/3

a=213 1/3

4 0
3 years ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
3 years ago
Will give brainlist if u answer answer ASAP
LuckyWell [14K]
I think it is B and C sorry if it’s not right but that’s what I think it is
8 0
3 years ago
HELPPP i'll mARK BRAINLIESTT PLZ HELPPPP,, kfibirbig5
Anna [14]
The answer would be D and E

Explanation: the number line shows any number less than 16, the filled in circle also means including 16. So it becomes any number 16 or less. So in both of the scenarios the max number of either students or dollars has to be 16.

Hope this helps
3 0
3 years ago
Read 2 more answers
QUESTION BELOW PLEASE HELP
Ad libitum [116K]

Answer:

61°

Step-by-step explanation:

180° - 119° = 61°

4 0
3 years ago
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