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3 years ago

True or false ??? Someone plz helpppp !!! this quiz is hard

Mathematics

2 answers:

elena-s [515]3 years ago

6 0

Answer:

True.

Step-by-step explanation:

Since they are all on the number line and some are negative, you would go back and go up instead. If you were to check again, it would be all on the number line.

Aleks [24]3 years ago

4 0

True ummm the top person was right

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Please help me!!!!!!!

Dmitrij [34]

9514 1404 393

Answer:

A) (-6, 8)

B) (x, y) ⇒ (-x, y)

Step-by-step explanation:

B) The rule for reflection across the y-axis is that the x-coordinate changes sign:

(x, y) ⇒ (-x, y)

A) To find the pre-image point, one can simply reflect the image back across the y-axis:

A'(6, 8) ⇒ A(-6, 8)

7 0

2 years ago

(X^2-2x+1)/x^2-x how do you simplify and divide this rational expression

Georgia [21]

$\frac{X^2-2x+1}{x^2-x} = \frac{(x-1)(x-1)}{x(x-1)} = \frac{x-1}{x}$

5 0

2 years ago

Read 2 more answers

Find the distance between the points given.<br><br> (2, 2) and (5, 5)

mario62 [17]

Distance between two points, d, is given by
$d= \sqrt{ ( x_{2} - x_{1}) ^{2} + (y_{2} - y_{1}) ^{2} }
$
where: (x1, y1) = (2, 2) and (x2, y2) = (5, 5)
$d= 
\sqrt{ ( 5 - 2) ^{2} + (5 - 2) ^{2} } \\ d= \sqrt{ (3)^{2} + 3^{2} } 
\\ d= \sqrt{9+9} \\ d= \sqrt{18} \\ d=3\sqrt{2} \ units$

7 0

3 years ago

Five years ago Kate was 5 times as old as her son. In 5 years her age will be 8 less than three times her son’s age at that time

torisob [31]

Answer: -19

Step-by-step explanation:

5xS

5-8x3= -19

3 0

2 years ago

I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

3 years ago